Back when i was preparing for the Web Component Developer exam, i had an idea of the requestURI and pattern mapping against the exact servlet. In simple words, the logic behind how the server maps the “<url-pattern>” tag and the <servlet-class> tag. I know that it is really a monstrous job, but then i wanted to try it using a simple array. Of course the code i wrote is buggy ( I myself found one big bug in there.) But for most cases, it works fine.
Here is my code. Download from here.
public class Navigation {
static String[] config= { “/test2″, “TestServlet2″, “/test”, “TestServlet” };
static String requestUri= “/test2/”;
public static void main(String[] args) {
System.out.println(”output” +new Navigation().getHandler(config, requestUri));
}
public String getHandler(String[] config, String requestUri)
{
System.out.println(”Request uri : “+requestUri);
int maxMatch=0; //store the length of the match that is the longest.
String currentMatch=null; //the most accurate match string
for (int i=0;i<config.length;i=i+2){
//looping through the array.
// Coz, you know that every odd String in the array is the Handler String,
//you can just skip them
System.out.println(”config[i] :”+config[i]);
if ((requestUri.startsWith(config[i]))){
if (config[i].length()>maxMatch){ //compare the length of the
//previously matched String, if any
maxMatch=config[i].length(); //if so, store it
System.out.println(”max match… “+config[i+1]);
currentMatch=config[i+1]; //Dont forget the String too
}
}
}
if (currentMatch!=null){
return currentMatch; //return it.
}
return “/”;
}
}
Tags: java, requesturi
